|
Search: id:A089313
|
|
|
| A089313 |
|
Write n in binary; a(n) = number represented by second block of 1's from the right. |
|
+0
5
|
|
| 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 1, 1, 0, 3, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 0, 3, 3, 3, 0, 7, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 0, 3, 3, 3, 3, 1, 3, 3, 0, 7, 7, 7, 0, 15, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 3, 3, 1, 7, 1, 1, 0, 3, 3, 3, 1, 3, 3, 1, 1
(list; graph; listen)
|
|
|
OFFSET
|
0,14
|
|
|
FORMULA
|
a(n) = 2^A089310(n)-1. - David Wasserman (wasserma(AT)spawar.navy.mil), Sep 09 2005
|
|
EXAMPLE
|
13 = 1101 so a(13) = 3.
|
|
PROGRAM
|
(PARI) { a(n) = local(b, l, r, c); b=binary(n); l=length(b); while(l&&b[l]==0, l--); while(l&&b[l]==1, l--); while(l&&b[l]==0, l--); r=0; c=0; while(l&&b[l], r+=2^c; l--; c++); r; } for(i=0, 200, print1(a(i), ", ")) (Klasen)
|
|
CROSSREFS
|
Cf. A089309-A089312.
Sequence in context: A035677 A143276 A101941 this_sequence A052998 A114516 A027185
Adjacent sequences: A089310 A089311 A089312 this_sequence A089314 A089315 A089316
|
|
KEYWORD
|
nonn,base
|
|
AUTHOR
|
N. J. A. Sloane (njas(AT)research.att.com), Dec 22 2003
|
|
EXTENSIONS
|
More terms from David Wasserman (wasserma(AT)spawar.navy.mil) and Lambert Klasen (Lambert.Klasen(AT)gmx.net), Sep 09 2005
|
|
|
Search completed in 0.002 seconds
|
