|
Search: id:A091050
|
|
|
| A091050 |
|
Number of divisors of n that are perfect powers. |
|
+0 3
|
|
| 1, 1, 1, 2, 1, 1, 1, 3, 2, 1, 1, 2, 1, 1, 1, 4, 1, 2, 1, 2, 1, 1, 1, 3, 2, 1, 3, 2, 1, 1, 1, 5, 1, 1, 1, 4, 1, 1, 1, 3, 1, 1, 1, 2, 2, 1, 1, 4, 2, 2, 1, 2, 1, 3, 1, 3, 1, 1, 1, 2, 1, 1, 2, 6, 1, 1, 1, 2, 1, 1, 1, 5, 1, 1, 2, 2, 1, 1, 1, 4, 4, 1, 1, 2, 1, 1, 1, 3, 1, 2, 1, 2, 1, 1, 1, 5, 1, 2, 2, 4, 1, 1
(list; graph; listen)
|
|
|
OFFSET
|
1,4
|
|
|
COMMENT
|
a(n)=1 iff n is square-free: a(A005117(n))=1, a(A013929(n))>1;
a(p^k)=k for p prime, k>0: a(A000961(n))=A025474(n);
not the same as A005361: a(72)=5 <> A005361(72)=6.
|
|
LINKS
|
Eric Weisstein's World of Mathematics, Perfect Power
Eric Weisstein's World of Mathematics, Divisor Function
|
|
FORMULA
|
a(n) = A073093(n)-A001221(n) = A001222(n)-A001221(n)+1. - David W. Wilson (davidwwilson(AT)comcast.net), Aug 28 2007
|
|
EXAMPLE
|
Divisors of n=108: {1,2,3,4,6,9,12,18,27,36,54,108}, a(108) =
#{1^2, 2^2, 3^2, 3^3, 6^2} = 5.
|
|
CROSSREFS
|
Cf. A091051, A001597, A000005.
Sequence in context: A051903 A157754 A072411 this_sequence A005361 A008479 A107345
Adjacent sequences: A091047 A091048 A091049 this_sequence A091051 A091052 A091053
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Dec 15 2003
|
|
|
Search completed in 0.002 seconds
|