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Search: id:A091457
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| A091457 |
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Greatest numerator of the remainder in a reciprocal expansion of 1. |
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+0
2
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OFFSET
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1,4
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COMMENT
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Conjecture: in the "extremal" expansion x_i = A000058(i) for i=1..n-3.
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FORMULA
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Let 1 = 1/x_1 + ... + 1/x_{n-1} + p/q, where 1/x_1>=...>=1/x_{n-1}>=p/q and (p, q)=1. a(n) = maximal p over all such expansions. Corresponded denominators sequence is A091458.
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EXAMPLE
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a(7) = 9770455 because 1 = 1/2 + 1/3 + 1/7 + 1/43 + 1/5413 + 1/5419 + 9770455/52975482882, and there is no expansion with larger numerator of the remainder.
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CROSSREFS
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Cf. A091458, A000058.
Sequence in context: A001059 A120608 A132549 this_sequence A100906 A126275 A059602
Adjacent sequences: A091454 A091455 A091456 this_sequence A091458 A091459 A091460
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KEYWORD
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frac,hard,nonn
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AUTHOR
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Max Alekseyev (maxal(AT)cs.ucsd.edu), Jan 11 2004
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