id:A092142 - OEIS Search Results

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Compute the continued fraction expansion of Pi; multiply each term by i, the square root of -1, compute this new continued fraction, and get a number with a real part equal to 0. Then compute the regular continued fraction of the imaginary part of that new number.

+0
1

2, 1, 5, 1, 12, 1, 301, 2, 78, 1, 14, 1, 1, 1, 10, 1, 1, 2, 4, 1, 4, 1, 94, 1, 3, 1, 1, 1, 8, 1, 5, 1, 2, 2, 4, 1, 10, 1, 8, 1, 10, 1, 13, 1, 158, 1, 42, 1, 18, 1, 21, 1, 8, 2, 2, 1, 3, 1, 2, 3, 23, 1, 8, 2, 39, 1, 3, 1, 1, 1, 7, 2, 2, 1, 7, 1, 5, 3, 53, 1, 14, 1, 6, 1, 15, 1, 14, 2, 5, 1, 28, 1, 1, 2, 4 (list; graph; listen)

	OFFSET	`0,1`
	PROGRAM	`(PARI) k=contfracpnqn(contfrac(Pi, 500)*I); contfrac(imag(k[1, 1]/k[2, 1]), 200)`
	CROSSREFS	`Sequence in context: A132081 A054251 A119763 this_sequence A006556 A108790 A117941` `Adjacent sequences: A092139 A092140 A092141 this_sequence A092143 A092144 A092145`
	KEYWORD	`easy,nonn`
	AUTHOR	`Thomas Baruchel (baruchel(AT)users.sourceforge.net), Mar 31 2004`

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Last modified August 29 17:54 EDT 2008. Contains 143238 sequences.

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