|
Search: id:A092693
|
|
|
| A092693 |
|
Sum of iterated phi(n). |
|
+0 5
|
|
| 0, 1, 3, 3, 7, 3, 9, 7, 9, 7, 17, 7, 19, 9, 15, 15, 31, 9, 27, 15, 19, 17, 39, 15, 35, 19, 27, 19, 47, 15, 45, 31, 35, 31, 39, 19, 55, 27, 39, 31, 71, 19, 61, 35, 39, 39, 85, 31, 61, 35, 63, 39, 91, 27, 71, 39, 55, 47, 105, 31, 91, 45, 55, 63, 79, 35, 101, 63, 79, 39, 109, 39, 111
(list; graph; listen)
|
|
|
OFFSET
|
1,3
|
|
|
COMMENT
|
Iannucci, Moujie and Cohen examine perfect totient numbers: n such that a(n) = n.
|
|
LINKS
|
Douglas E. Iannucci, Deng Moujie and Graeme L. Cohen, On Perfect Totient Numbers, J. Integer Sequences, 6 (2003), #03.4.5.
|
|
FORMULA
|
a(1) = 0, a(n) = phi(n) + a(phi(n))
a(n) = A053478(n) - n. - Vladeta Jovovic (vladeta(AT)Eunet.yu), Jul 02 2004
|
|
EXAMPLE
|
a(100) = 71 because the iterations of phi (40, 16, 8, 4, 2, 1) sum to 71.
|
|
MATHEMATICA
|
nMax=100; a=Table[0, {nMax}]; Do[e=EulerPhi[n]; a[[n]]=e+a[[e]], {n, 2, nMax}]; a
Table[Plus @@ FixedPointList[EulerPhi, n] - (n + 1), {n, 72}] - Alonso Delarte (alonso.delarte(AT)gmail.com), Jan 29 2007
|
|
CROSSREFS
|
Cf. A003434 (iterations of phi(n) needed to reach 1), A092694 (iterated phi product).
Cf. A082897 and A091847 (perfect totient numbers).
Sequence in context: A036840 A030316 A034257 this_sequence A134661 A135434 A069949
Adjacent sequences: A092690 A092691 A092692 this_sequence A092694 A092695 A092696
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
T. D. Noe (noe(AT)sspectra.com), Mar 04 2004
|
|
|
Search completed in 0.002 seconds
|