0,3

For n > 0, a(2n+1) is represented as a string of n 2's and a(2n) as a string of (n-1) 1's followed by a 2.

a(8)= 1112 because A078008(8)= 86 (in base 10) = 64 + 16 + 4 + 2 = 1*(4^3)+1*

(4^2)+1*(4^1)+2.

Cf. A081857.

Adjacent sequences: A092897 A092898 A092899 this_sequence A092901 A092902 A092903

Sequence in context: A059187 A054916 A140431 this_sequence A164961 A122007 A137782

easy,nonn

Paul Barry (pbarry(AT)wit.ie), Mar 12 2004