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Search: id:A093445
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| A093445 |
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The triangular triangle. |
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+0 4
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| 1, 3, 3, 6, 9, 6, 10, 18, 17, 10, 15, 30, 33, 27, 15, 21, 45, 54, 51, 39, 21, 28, 63, 80, 82, 72, 53, 28, 36, 84, 111, 120, 114, 96, 69, 36, 45, 108, 147, 165, 165, 150, 123, 87, 45, 55, 135, 188, 217, 225, 215, 190, 153, 107, 55, 66, 165, 234, 276, 294, 291, 270, 234
(list; table; graph; listen)
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OFFSET
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1,2
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COMMENT
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The n-th row of the triangular table begins by considering n triangular numbers (A000217) in order. Now segregate them into n groups beginning with n members in the first group, n-1 members in the second group, etc. Now sum each group. Thus the first term is the sum of first n numbers = n(n+1)/2, the second term is the sum of the next n-1 terms (from n+1 to 2n-1), the third term is the sum of the next n-2 terms (2n to 3n-3), etc. and the last term is simply n(n+1)/2. This triangle can be called as triangular triangle. The sequence contains the triangle by rows.
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FORMULA
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T(n) is the n-th Triangular number = C(n+1, 2) = n(n+1)/2 = 0+1+2+...+n. TT(n, k) is the k-th term of the n-th row, 0<k<=n.
TT(n, k) = T(k*n - T(k - 1)) - T((k - 1)*n - T(k - 2)).
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EXAMPLE
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1
3, 3
6, 9, 6
10, 18, 17, 10
15, 30, 33, 27, 15
21, 45, 54, 51, 39, 21
28, 63, 80, 82, 72, 53, 28
36, 84, 111, 120, 114, 96, 69, 36
The row for n = 4 is (1+2+3+4), (5+6+7), (8+9), 10 => 10 18 17 10.
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MATHEMATICA
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T[n_] := n(n + 1)/2; TT[n_, k_] := T[k*n - T[k - 1]] - T[(k - 1)*n - T[k - 2]]; Flatten[ Table[ TT[n, k], {n, 1, 11}, {k, 1, n}]] (from Robert G. Wilson v Apr 24 2004)
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CROSSREFS
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Cf. A093446. TT(n, 1) = TT(n, n) = T(n) = A000217. TT(n, 2) = A045943. TT(n, n-1) = A014209. TT(0, k) = A027480.
Sequence in context: A104715 A164743 A110769 this_sequence A098358 A136289 A128012
Adjacent sequences: A093442 A093443 A093444 this_sequence A093446 A093447 A093448
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KEYWORD
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nonn,nice,tabl
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AUTHOR
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Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Apr 02 2004
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EXTENSIONS
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Edited, corrected and extended by Robert G. Wilson v (rgwv(AT)rgwv.com), Apr 24 2004
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