|
Search: id:A093461
|
|
|
| A093461 |
|
a(1)=1, a(n)=2[n^(n-1)-1]/(n-1) for n>=2. |
|
+0 4
|
|
| 1, 2, 8, 42, 312, 3110, 39216, 599186, 10761680, 222222222, 5187484920, 135092431034, 3883014187080, 122109965116022, 4170418003627232, 153722867280912930, 6082648984458358560, 257166065851611356702
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
Proposition: n^(n-1) -1 == 0 (mod (n-1)^2). Hence a(n) == 0 mod (n-1).
a(n) is the common difference of the arithmetic progression in row n of A111568. Written in base n, a(n) has n-1 digits equal to 2 (for example, a(10)=222222222). - Emeric Deutsch (deutsch(AT)duke.poly.edu), Aug 08 2005
|
|
FORMULA
|
a(1) = 1, a(n) = 2*{n^(n-1) -1}}/{n-1} for n >1.
|
|
MAPLE
|
a:=proc(n) if n=1 then 1 else 2*(n^(n-1)-1)/(n-1) fi end: seq(a(n), n=1..20); (Deutsch)
|
|
MATHEMATICA
|
f[n_] := (2*n^(n-1) - 2)/(n-1); Table[f[i], {i, 2, 30}] (Propper)
|
|
CROSSREFS
|
Cf. A093460, A093462.
Cf. A111568.
Sequence in context: A078592 A052646 A002856 this_sequence A153524 A153552 A012917
Adjacent sequences: A093458 A093459 A093460 this_sequence A093462 A093463 A093464
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Apr 05 2004
|
|
EXTENSIONS
|
More terms from Emeric Deutsch (deutsch(AT)duke.poly.edu) and Ryan Propper (rpropper(AT)stanford.edu), Aug 08 2005
|
|
|
Search completed in 0.002 seconds
|