0,3

Inverse binomial transform of A000129(2n-1). a(n+2)/4=A057087(n).

Tanya Khovanova, Recursive Sequences

a(n)=(2+2sqrt(2))^n(1/2-sqrt(2)/4)+(2-2sqrt(2))^n(1/2+sqrt(2)/4).

Cf. A001653.

Sequence in context: A009318 A081682 A068788 this_sequence A106568 A075581 A020080

Adjacent sequences: A094010 A094011 A094012 this_sequence A094014 A094015 A094016

easy,nonn

Paul Barry (pbarry(AT)wit.ie), Apr 21 2004