|
Search: id:A094200
|
|
|
| A094200 |
|
a(n)=16*n^4+32*n^3+36*n^2+20*n+3. |
|
+0 3
|
|
| 3, 107, 699, 2547, 6803, 15003, 29067, 51299, 84387, 131403, 195803, 281427, 392499, 533627, 709803, 926403, 1189187, 1504299, 1878267, 2318003, 2830803, 3424347, 4106699, 4886307, 5772003, 6773003, 7898907, 9159699, 10565747
(list; graph; listen)
|
|
|
OFFSET
|
0,1
|
|
|
COMMENT
|
Let x(n)=(1/2)*(-(2*n+1)+sqrt((2*n+1)^2+4)) and f(k)=(-1)*sum(i=1,k,sum(j=1,i,(-1)^floor(j*x(n)))), then a(n)=k is the least integer k>0 such that f(k)=0.
|
|
REFERENCES
|
B. Cloitre, On parity properties of certain Beatty sequences, in preparation 2004
|
|
PROGRAM
|
(PARI) a(n)=16*n^4+32*n^3+36*n^2+20*n+3
|
|
CROSSREFS
|
Cf. A094201, A085005.
Sequence in context: A139921 A142509 A023325 this_sequence A003705 A146214 A061308
Adjacent sequences: A094197 A094198 A094199 this_sequence A094201 A094202 A094203
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Benoit Cloitre (benoit7848c(AT)orange.fr), May 25 2004
|
|
|
Search completed in 0.002 seconds
|