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Search: id:A094293
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| A094293 |
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a(1)= 1, a(2) = 2,let the index of first occurrence of n be k then from a(k+1) onwards the next n*(k-1) terms are the first (k-1) terms repeated n times, a(k+1) = a(1), a(k+2) = a(2) etc. |
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+0
2
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| 1, 2, 1, 1, 3, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 4, 1, 2, 1, 1, 3, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 3, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 3, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 3, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 5, 1, 2, 1, 1, 3, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 4
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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Let r be the index of the first occurrence of n-1 then the index of first occurrence of n is n*(r-1) + r + 1.
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EXAMPLE
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a(5) = 3 and the first four terms are 1,2,1,1. hence the next 12 terms are 1,2,1,1,1,2,1,1,1,2,1,1, and a(18) = 4 (the first occurrence) and so on.
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CROSSREFS
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Cf. A001511.
Sequence in context: A086599 A030272 A057898 this_sequence A036036 A076259 A107359
Adjacent sequences: A094290 A094291 A094292 this_sequence A094294 A094295 A094296
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KEYWORD
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nonn,uned
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AUTHOR
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Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Apr 28 2004
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