0,3

G.f. satisfies: A(x) = A(x*G094601(x)). a(2n) = A094601(n)*(n+1) for n>=0. Sum_{n>=1} a(2n-1)/n*x^n = log(G094601(x)).

log(G094601(x)) = log(1+x+3x^2+12x^3+50x^4+...) = (x+5x^2/2+28x^3/3+145x^4/4+...).

Terms are formed from main and adjacent diagonals in the table of

successive self-convolutions of this sequence:

[_1,_1,2,5,9,28,48,145,250,831,1404,4664,...]

[1,_2,_5,14,32,94,213,588,1343,3726,...]

[1,3,_9,_28,75,225,590,1656,4287,11780,...]

[1,4,14,_48,_145,456,1318,3864,10824,30684,...]

[1,5,20,75,_250,_831,2590,7980,23755,70155,...]

[1,6,27,110,399,_1404,_4664,15102,47355,145880,...]

[1,7,35,154,602,2240,_7875,_26748,87892,282093,...]

[1,8,44,208,870,3416,12648,_44960,_154265,514920,...]

[1,9,54,273,1215,5022,19512,72423,_258777,_896644,..]

Cf. A094557, A094601.

Sequence in context: A026297 A109742 A072979 this_sequence A139796 A086586 A105456

Adjacent sequences: A094597 A094598 A094599 this_sequence A094601 A094602 A094603

nonn

Paul D. Hanna (pauldhanna(AT)juno.com), May 13 2004