0,3

a(n) = A094600(n)/(n+1) for n>=0. G.f.: A(x) = exp(Sum_{n>=1}A094600(2n-1)/n*x^n), where A(x) = A(x/G094600(x)).

log(A(x)) = Sum_{n>=1}A094600(2n-1)/n*x^n = (x+5x^2/2+28x^3/3+145x^4/4+...).

Cf. A094600.

Sequence in context: A105479 A151180 A151181 this_sequence A009024 A043291 A135343

Adjacent sequences: A094598 A094599 A094600 this_sequence A094602 A094603 A094604

nonn

Paul D. Hanna (pauldhanna(AT)juno.com), May 13 2004