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Search: id:A095734
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| A095734 |
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Asymmetricity-index for Zeckendorf-expansion A014417(n) of n. |
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+0
3
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| 0, 0, 1, 1, 0, 1, 0, 2, 1, 0, 2, 1, 0, 1, 0, 2, 2, 1, 2, 1, 3, 1, 0, 2, 2, 1, 1, 0, 2, 2, 1, 3, 1, 0, 1, 0, 2, 2, 1, 2, 1, 3, 2, 1, 3, 3, 2, 2, 1, 3, 1, 0, 3, 2, 4, 1, 0, 2, 2, 1, 2, 1, 3, 1, 0, 2, 2, 1, 2, 1, 3, 3, 2, 1, 0, 2, 2, 1, 3, 1, 0, 3, 2, 4, 2, 1, 3, 1, 0, 1, 0, 2, 2, 1, 2, 1, 3, 2, 1, 3, 3, 2, 2, 1, 3
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OFFSET
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0,8
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COMMENT
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Least number of flips of "fibits" (changing either 0 to 1 or 1 to 0 in Zeckendorf-expansion A014417(n)) so that a palindrome is produced.
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EXAMPLE
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The integers 0 and 1 look as '0' and '1' also in Fibonacci-representation,
and being palindromes, a(0) and a(1) = 0.
2 has Fibonacci-representation '10', which needs a flip of other 'fibit',
that it would become a palindrome, thus a(2) = 1. Similarly 3 has representation
'100', so flipping for example the least significant fibit, we get '101',
thus a(3)=1 as well. 7 (= F(3)+F(5)) has representation '1010', which needs
two flips to produce a palindrome, thus a(7)=2. Here F(n) = A000045(n).
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CROSSREFS
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a(n) = A037888(A003714(n)). A094202 gives the positions of zeros. Cf. also A095732.
Sequence in context: A138514 A143540 A030200 this_sequence A137269 A112201 A112203
Adjacent sequences: A095731 A095732 A095733 this_sequence A095735 A095736 A095737
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KEYWORD
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base,nonn
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AUTHOR
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Antti Karttunen (Antti.Karttunen(AT)iki.fi), Jun 05 2004
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