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Search: id:A095794
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A095794 a(n) = A005449(n) - 1, where A005449 = second pentagonal numbers. +0
9
1, 6, 14, 25, 39, 56, 76, 99, 125, 154, 186, 221, 259, 300, 344, 391, 441, 494, 550, 609, 671, 736, 804, 875, 949, 1026, 1106, 1189, 1275, 1364, 1456, 1551, 1649, 1750, 1854, 1961, 2071, 2184, 2300, 2419, 2541, 2666, 2794, 2925, 3059, 3196, 3336, 3479, 3625 (list; graph; listen)
OFFSET

1,2

COMMENT

a(n) = A126890(n,n-2) for n>1. - Reinhard Zumkeller (reinhard.zumkeller(AT)lhsystems.com), Dec 30 2006

FORMULA

a(n) = (3/2)n^2 + (1/2)n - 1. a(n+3), (n>3) = 3*a(n+2) - 3*a(n+1) + a(n). a(n+1) right term in M^n * [1 1 1].

sum (n+j-1,j=0..n). - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Sep 12 2006

Row sums of triangle A131414.

Equals binomial transform of (1, 5, 3, 0, 0, 0,...). Equals A051340 * (1, 2, 3,...).

G.f.: x*(-1-3*x+x^2)/(-1+x)^3 = 1-3/(-1+x)^3-4/(-1+x)^2 . - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Nov 19 2007

EXAMPLE

1. a(4) = 25 = A005449(4) - 1

2. a(5) = 39 = f(n), n=5 in (3/2)n^2 + (1/2)n - 1.

3. a(7) = 76 = 3*56 - 3*39 + 25

4. a(5) = 39 = right term of M^4 * [1 1 1] = [1 5 39].

MAPLE

A005449 := proc(n) RETURN(n*(3*n+1)/2) ; end: A095794 := proc(n) RETURN(A005449(n)-1) ; end: for n from 1 to 100 do printf("%a, ", A095794(n)) ; od: - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jun 23 2006

a[0]:=0:a[1]:=1:for n from 2 to 50 do a[n]:=2*a[n-1]-a[n-2]-3 od: seq(-a[n], n=2..50); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Feb 18 2008

CROSSREFS

Cf. A005449, A051340, A131414.

Sequence in context: A028557 A083657 A010740 this_sequence A119867 A026055 A131951

Adjacent sequences: A095791 A095792 A095793 this_sequence A095795 A095796 A095797

KEYWORD

nonn

AUTHOR

Gary W. Adamson (qntmpkt(AT)yahoo.com), Jun 06 2004, Jul 08 2007

EXTENSIONS

Corrected and extended by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jun 23 2006

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Last modified July 24 12:00 EDT 2008. Contains 142294 sequences.


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