|
Search: id:A096545
|
|
|
| A096545 |
|
Ordered z such that, for 0<x<y<z, the primitive quadruples (x,y,z,w) satisfy x^3 + y^3 + z^3 = w^3. |
|
+0 4
|
|
| 5, 8, 17, 18, 21, 22, 27, 33, 37, 37, 40, 41, 44, 49, 53, 54, 57, 61, 64, 65, 66, 69, 69, 70, 72, 74, 75, 78, 79, 79, 79, 84, 85, 86, 86, 87, 89, 90, 92, 96, 97, 97, 97, 99, 101, 102, 102, 104, 105, 108, 114, 116, 118, 121, 122, 123, 124, 124, 128, 131, 136, 136, 137
(list; graph; listen)
|
|
|
OFFSET
|
1,1
|
|
|
COMMENT
|
For corresponding values w see A096546.
|
|
REFERENCES
|
Y. Perelman, Solutions to x^3 + y^3 + z^3 = u^3, Mathematics can be Fun, pp. 316-9 Mir Moscow 1985.
|
|
LINKS
|
Fred Richman, Sums of Three Cubes
|
|
EXAMPLE
|
21 and 22, for instance, are terms because we have: 18^3 + 19^3 + 21^3 = 28^3 and 4^3 + 17^3 + 22^3 = 25^3.
|
|
CROSSREFS
|
Primitive quadruples (x, y, z, w) = (A095868, A095867, A096545, A096546).
Sequence in context: A058566 A153363 A154119 this_sequence A075338 A088646 A090679
Adjacent sequences: A096542 A096543 A096544 this_sequence A096546 A096547 A096548
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Lekraj Beedassy (blekraj(AT)yahoo.com), Jun 25 2004
|
|
EXTENSIONS
|
Edited, corrected and extended by Ray Chandler (rayjchandler(AT)sbcglobal.net), Jun 28 2004
|
|
|
Search completed in 0.002 seconds
|