|
Search: id:A098262
|
|
|
| A098262 |
|
First differences of Chebyshev polynomials S(n,627)=A098260(n) with Diophantine property. |
|
+0 4
|
|
| 1, 626, 392501, 246097501, 154302740626, 96747572275001, 60660573513685001, 38034082845508220626, 23847309283560140647501, 14952224886709362677762501, 9375021156657486838816440626
(list; graph; listen)
|
|
|
OFFSET
|
0,2
|
|
|
COMMENT
|
(25*b(n))^2 - 629*a(n)^2 = -4 with b(n)=A098261(n) give all positive solutions of this Pell equation.
|
|
LINKS
|
Tanya Khovanova, Recursive Sequences
Index entries for sequences related to Chebyshev polynomials.
|
|
FORMULA
|
a(n)= ((-1)^n)*S(2*n, 25*I) with the imaginary unit I and the S(n, x)=U(n, x/2) Chebyshev polynomials.
G.f.: (1-x)/(1-627*x+x^2).
a(n)= S(n, 627) - S(n-1, 627) = T(2*n+1, sqrt(629)/2)/(sqrt(629)/2), with S(n, x)=U(n, x/2) Chebyshev's polynomials of the second kind, A049310. S(-1, x)= 0 = U(-1, x) and T(n, x) Chebyshev's polynomials of the first kind, A053120.
a(n)=627*a(n-1)-a(n-2), n>1 ; a(0)=1, a(1)=626 . [From Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Nov 18 2008]
|
|
EXAMPLE
|
All positive solutions of Pell equation x^2 - 629*y^2 = -4 are
(25=25*1,1), (15700=25*628,626), (9843875=25*393755,392501),
(6172093925=25*246883757,246097501), ...
|
|
CROSSREFS
|
Sequence in context: A158383 A031613 A031728 this_sequence A031523 A129974 A031703
Adjacent sequences: A098259 A098260 A098261 this_sequence A098263 A098264 A098265
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
Wolfdieter Lang (wolfdieter.lang_AT_physik_DOT_uni-karlsruhe_DOT_de), Sep 10 2004
|
|
|
Search completed in 0.002 seconds
|