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Search: id:A098289
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| A098289 |
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Let a(1)=0. Then a(i+1)=position of first occurrence of a(i) in decimal expansion of ln(2). |
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+0
15
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| 0, 9, 2, 22, 419, 591, 898, 915, 285, 3618, 10367, 5396, 1192, 8251, 13198, 16050, 47987, 146191, 2518028, 7744270, 16819386
(list; graph; listen)
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OFFSET
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1,2
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LINKS
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Charles R Greathouse IV, Home Page [Listed in lieu of email address]
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EXAMPLE
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ln(2) = 0.693147180559945309417232121458...
For example, a(2)=9 because the 9th digit of ln(2) after decimal point is 0 and this is the first occurrence of 0.
a(3)=2 because 2nd decimal digit of ln(2) is 9, a(4)=22 because 22nd decimal digit of ln(2) is 2 and so on.
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CROSSREFS
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Cf. A098266 (for e recurrence), A097614 (for Pi recurrence).
Sequence in context: A090298 A094581 A040080 this_sequence A152020 A055516 A096042
Adjacent sequences: A098286 A098287 A098288 this_sequence A098290 A098291 A098292
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KEYWORD
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more,nonn
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AUTHOR
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Mark Hudson (mrmarkhudson(AT)hotmail.com), Sep 02 2004
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EXTENSIONS
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Edited by N. J. A. Sloane (njas(AT)research.att.com), Oct 15 2006
More terms from Charles R. Greathouse IV Oct 09 2006
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