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Search: id:A098290
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| A098290 |
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Recurrence sequence based on positions of digits in decimal places of Zeta(3) (Apery's constant). |
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+0
12
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| 0, 2, 1, 10, 208, 380, 394, 159, 10, 208, 380, 394, 159, 10, 208, 380, 394, 159, 10
(list; graph; listen)
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OFFSET
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0,2
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COMMENT
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This recurrence sequence starts to repeat quite quickly because 1 appears at the 10th digit of Zeta(3), which is also where 159 starts. Do all recurrence relations of this kind for transcendental numbers eventually repeat?
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FORMULA
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a(1)=0, p(i)=position of first occurrence of a(i) in decimal places of Zeta(3), a(i+1)=p(i).
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EXAMPLE
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Zeta(3)=1.2020569031595942853997...
a(1)=0, a(2)=2 because 2nd decimal = 0, a(3)=1 because first digit = 2, etc
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CROSSREFS
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Cf. A098266 (for e version), A097614 (for Pi version), A098289 (for ln(2) version), A002117 for digits of Zeta(3).
Sequence in context: A071926 A133103 A054781 this_sequence A139393 A037916 A016546
Adjacent sequences: A098287 A098288 A098289 this_sequence A098291 A098292 A098293
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KEYWORD
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nonn
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AUTHOR
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Mark Hudson (mrmarkhudson(AT)hotmail.com), Sep 02 2004
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