|
Search: id:A098756
|
|
|
| A098756 |
|
Smallest available integer which fits into the repeating pattern 9876543210. |
|
+0
1
|
|
| 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 98, 76, 54, 32, 10, 987, 65, 43, 210, 9876, 543, 2109, 87, 654, 3210, 98765, 432, 109, 876, 5432, 1098, 765, 43210, 987654, 32109, 8765, 432109, 87654, 321098, 7654, 3210987, 6543
(list; graph; listen)
|
|
|
OFFSET
|
1,1
|
|
|
COMMENT
|
a(n) must be chosen so its rightmost digit is not 1, with the exception a(n)=1.
|
|
FORMULA
|
To calculate the n-th term (n>10), find the greatest i<n such that first digit of a(i)=(last digit of a(n-1))-1 mod 10; then a(n) is a(i) augmented with the next digit (or next 2 digits if next digit is 1) - Sam Alexander (amnalexander(AT)yahoo.com), Jan 04 2005
|
|
EXAMPLE
|
To find the next term after 5432, we look for the most recent term beginning with 1 (1=2-1), which is 109. Augment 109 to get 1098.
|
|
CROSSREFS
|
Sequence in context: A109910 A084019 A061601 this_sequence A112454 A138531 A030076
Adjacent sequences: A098753 A098754 A098755 this_sequence A098757 A098758 A098759
|
|
KEYWORD
|
base,easy,nonn,more
|
|
AUTHOR
|
Eric Angelini (eric.angelini(AT)kntv.be), Oct 01 2004
|
|
EXTENSIONS
|
Corrected and extended by Sam Alexander (amnalexander(AT)yahoo.com), Jan 04 2005
|
|
|
Search completed in 0.002 seconds
|
