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Search: id:A098970
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| A098970 |
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Numbers n such that (12*n)^2 can be expressed as the sum of the cubes of two distinct primes. |
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+0
5
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| 19, 67695, 411292, 1134035, 1184876, 2112836, 2455255, 4073384, 11293009, 16171470, 18589912, 34388501, 63609329, 63711615, 117446600, 166530856, 284034387, 449805631, 637548135, 685361103, 783484793, 888180400, 1121365940
(list; graph; listen)
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OFFSET
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1,1
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COMMENT
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This sequence resulted from a discussion on the seqfan mailing list started by Ed Pegg, Jr.
Dean Hickerson and Paul C. Leopardi have shown that if a and b are distinct primes with a^3 + b^3 = c^2, then c must be divisible by 12.
12*n is a subset of A099426. - Hans Havermann (pxp(AT)rogers.com), Oct 24 2004
All terms of this sequence are of the form M*N*(3*M^4+N^4)/2 for some pair M,N of relatively prime positive integers of opposite parity. For each n, A099806[n]^3 + A099807[n]^3 = (12*A098970[n])^2. - James Buddenhagen (jbuddenh(AT)gmail.com), Oct 26 2004
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LINKS
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James Buddenhagen, Two Primes Cubed which Sum to a Square.
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CROSSREFS
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Cf. A099426.
Cf. A099806, A099807, A099808, A099809.
Sequence in context: A125043 A068734 A034207 this_sequence A013764 A078353 A070632
Adjacent sequences: A098967 A098968 A098969 this_sequence A098971 A098972 A098973
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KEYWORD
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nonn
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AUTHOR
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Hugo Pfoertner (hugo(AT)pfoertner.org), Oct 24 2004
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EXTENSIONS
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More terms from James Buddenhagen (jbuddenh(AT)gmail.com), Oct 26 2004
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