|
Search: id:A099307
|
|
|
| A099307 |
|
Least k such that the k-th arithmetic derivative of n is zero, or 0 if no k exists. |
|
+0 5
|
|
| 1, 2, 2, 0, 2, 3, 2, 0, 4, 3, 2, 0, 2, 5, 0, 0, 2, 5, 2, 0, 4, 3, 2, 0, 4, 0, 0, 0, 2, 3, 2, 0, 6, 3, 0, 0, 2, 5, 0, 0, 2, 3, 2, 0, 0, 5, 2, 0, 6, 0, 0, 0, 2, 0, 0, 0, 4, 3, 2, 0, 2, 7, 0, 0, 6, 3, 2, 0, 0, 3, 2, 0, 2, 0, 0, 0, 6, 3, 2, 0, 0, 3, 2, 0, 4, 0, 0, 0, 2, 0, 0, 0, 4, 7, 0, 0, 2, 7, 0, 0, 2, 0, 2, 0, 3
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
Denote the k-th derivative of n by d(n,k). We know that we can stop taking derivatives if either d(n,k) = 0 or d(n,k) has a factor of the form p^p for prime p. In the latter case, the derivatives will stay constant or grow without bound.
|
|
REFERENCES
|
See A003415
|
|
MATHEMATICA
|
dn[0]=0; dn[1]=0; dn[n_]:=Module[{f=Transpose[FactorInteger[n]]}, If[PrimeQ[n], 1, Plus@@(n*f[[2]]/f[[1]])]]; Table[k=0; d=n; done=False; While[If[d==1, done=True, f=FactorInteger[d]; Do[If[f[[i, 1]]<=f[[i, 2]], done=True], {i, Length[f]}]]; !done, k++; d=dn[d]]; If[d==1, k+1, 0], {n, 200}]
|
|
CROSSREFS
|
Cf. A003415 (arithmetic derivative of n), A099308 (numbers whose k-th arithmetic derivative is zero for some k), A099309 (numbers whose k-th arithmetic derivative is nonzero for all k).
Sequence in context: A141661 A080769 A143539 this_sequence A072738 A165316 A141058
Adjacent sequences: A099304 A099305 A099306 this_sequence A099308 A099309 A099310
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
T. D. Noe (noe(AT)sspectra.com), Oct 12 2004
|
|
|
Search completed in 0.002 seconds
|