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A100066 Expansion of x/((1-x)sqrt(1-4x^2)). +0
4
0, 1, 1, 3, 3, 9, 9, 29, 29, 99, 99, 351, 351, 1275, 1275, 4707, 4707, 17577, 17577, 66197, 66197, 250953, 250953, 956385, 956385, 3660541, 3660541, 14061141, 14061141, 54177741, 54177741, 209295261, 209295261, 810375651, 810375651 (list; graph; listen)
OFFSET

0,4

COMMENT

An inverse Chebyshev transform of x/(1-x+x^2), where the Chebyshev transform of g(x) is ((1-x^2)/(1+x^2))g(x/(1+x^2)) and the inverse transform maps a g.f. A(x) to (1/sqrt(1-4x^2))A(xc(x^2)) where c(x) is the g.f. of the Catalan numbers A000108.

FORMULA

a(n)=sum{k=0..n, if(mod(n-k)=2, binomial(n, (n-k)/2)*2sin(pi*k/3)/sqrt(3)}; a(n)=sum{k=0..n, binomial(n, (n-k)/2)(1+(-1)^(n-k))sin(pi*k/3)/sqrt(3)}; a(n)=sum{k=0..n, binomial(n-1, (n-1)/2)(1-(-1)^k)/2}.

a(n+1)=sum{k=0..floor(n/2), binomial(2k, k)}=sum{k=0..n, binomial(k, k/2)*(1+(-1)^k)/2};

a(2n-1) = a(2n) = A006134(n-1) = Sum[ (2k)!/(k!)^2, {k,0,n} ] for n>0. - Alexander Adamchuk (alex(AT)kolmogorov.com), Feb 23 2007

MAPLE

a:=n->sum(binomial(2*j, j), j=0..n): seq(a(n/2), n=-1..33); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Apr 30 2007

CROSSREFS

Cf. A006134.

Sequence in context: A146788 A147244 A146575 this_sequence A117783 A121445 A121074

Adjacent sequences: A100063 A100064 A100065 this_sequence A100067 A100068 A100069

KEYWORD

easy,nonn

AUTHOR

Paul Barry (pbarry(AT)wit.ie), Nov 02 2004

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Last modified November 25 20:09 EST 2009. Contains 167514 sequences.


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