|
Search: id:A101180
|
|
|
| A101180 |
|
Sequence a(n) such that 19*(a(n)^2)+19*a(n)+1 = a square. |
|
+0
1
|
|
| 0, 8, 671, 15639, 42159, 981911, 77624048, 1807894920, 4873553880, 113507005568, 8973184757831, 208989037004319, 563373081435879
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
Define a(1)=0, a(2)=8, a(3)=671, a(4)=15639, a(5)=42159, a(6)=981911, the first 6 terms found for the sequence then a(7)=57799*(2*a(3)+1)-a(2)-1, a(8)=57799*(2*a(4)+1)-a(1)-1 for n>8 a(n)=57799*(2*a(n-4)+1)-a(n-8)-1 remark:57799 = 38*39*39+1 =2*19*(39^2)+1
|
|
CROSSREFS
|
Sequence in context: A015106 A099126 A105840 this_sequence A128875 A037076 A116245
Adjacent sequences: A101177 A101178 A101179 this_sequence A101181 A101182 A101183
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Pierre CAMI (pierrecami(AT)tele2.fr), Apr 06 2005
|
|
|
Search completed in 0.002 seconds
|
