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Search: id:A101913
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| A101913 |
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G.f. satisfies: A(x) = 1/(1 + x*A(x^3)) and also the continued fraction: 1+x*A(x^4) = [1;1/x,1/x^3,1/x^9,1/x^27,...,1/x^(3^(n-1)),...]. |
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+0
3
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| 1, -1, 1, -1, 2, -3, 4, -6, 9, -13, 19, -28, 41, -61, 90, -132, 195, -288, 424, -625, 922, -1359, 2004, -2955, 4356, -6423, 9471, -13963, 20587, -30355, 44755, -65987, 97293, -143449, 211503, -311844, 459785, -677912, 999524, -1473709, 2172854, -3203685, 4723551, -6964461, 10268490, -15139986
(list; graph; listen)
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OFFSET
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0,5
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PROGRAM
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(PARI) {a(n)=local(A); A=1-x; for(i=1, n\3+1, A=1/(1+x*subst(A, x, x^3)+x*O(x^n))); polcoeff(A, n, x)} (PARI) {a(n)=local(M=contfracpnqn(concat(1, vector(ceil(log(n+1)/log(3))+1, n, 1/x^(3^(n-1)))))); polcoeff(M[1, 1]/M[2, 1]+x*O(x^(4*n+1)), 4*n+1)}
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CROSSREFS
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Cf. A101912, A101914-A101918.
Sequence in context: A068921 A078012 A135851 this_sequence A121653 A061418 A136423
Adjacent sequences: A101910 A101911 A101912 this_sequence A101914 A101915 A101916
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KEYWORD
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sign
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AUTHOR
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Paul D. Hanna (pauldhanna(AT)juno.com), Dec 20 2004
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