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Search: id:A102476
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| A102476 |
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Least modulus with 2^n square roots of 1. |
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+0
2
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| 1, 3, 8, 24, 120, 840, 9240, 120120, 2042040, 38798760, 892371480, 25878772920, 802241960520, 29682952539240, 1217001054108840, 52331045326680120, 2459559130353965640, 130356633908760178920, 7691041400616850556280
(list; graph; listen)
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OFFSET
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0,2
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COMMENT
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The number of square roots of 1 in any modulus is a power of 2.
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FORMULA
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a(n) = 4(p(n-1))# = 4*A002110(n-1) for n >= 2. Least k with A060594(k) = 2^n.
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EXAMPLE
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a(3) = 24 because 24 is the least modulus with 2^3 square roots of 1, namely 1,5,7,11,13,17,19,23.
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CROSSREFS
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Cf. A060594, A002110.
Sequence in context: A071016 A002104 A102919 this_sequence A123638 A057420 A076049
Adjacent sequences: A102473 A102474 A102475 this_sequence A102477 A102478 A102479
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KEYWORD
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easy,nonn
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AUTHOR
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David W. Wilson (davidwwilson(AT)comcast.net), Jan 10 2005
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