0,2

a(n)=sum{k=0..n, (n-k)^k}+n=sum{k=0..n, k^(n-k)}+n; a(n+1)=A026898(n)+n+1.

Sequence in context: A112740 A136408 A103104 this_sequence A024826 A102114 A102115

Adjacent sequences: A103477 A103478 A103479 this_sequence A103481 A103482 A103483

easy,nonn

Paul Barry (pbarry(AT)wit.ie), Feb 07 2005