1,1

a(3)=211 because 211 is the smallest prime formed from reverse concatenation of 3 consecutive fibonacci numbers i.e. 1,1 and 2.

Sequence in context: A070256 A020450 A036229 this_sequence A042805 A088639 A162385

Adjacent sequences: A104334 A104335 A104336 this_sequence A104338 A104339 A104340

base,nonn

Shyam Sunder Gupta (guptass(AT)rediffmail.com), Apr 17 2005