|
Search: id:A104480
|
|
|
| A104480 |
|
Numbers n such that the period length P(n) of the Fibonacci sequence modulo n is a perfect square. |
|
+0 1
|
|
| 1, 7, 17, 21, 25, 34, 68, 97, 119, 127, 133, 136, 152, 175, 189, 238, 266, 275, 323, 337, 343, 357, 378, 381, 391, 399, 425, 437, 475, 476, 505, 525, 532, 544, 577, 608, 621, 625, 646, 647, 679, 707, 714, 749, 755, 756, 782, 798, 850, 864, 874, 889, 950, 952
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
144 appears to be the most common perfect square.
|
|
EXAMPLE
|
Let P(n) be the period length of the modulo n Fibonacci sequence (also called the Pisano period). Then {P(n)}=1,3,8,6,20,24,16,12,... and a(2)=7 because the second perfect square in {P(n)} occurs when n=7.
|
|
CROSSREFS
|
Cf. A001175.
Sequence in context: A106123 A156011 A155774 this_sequence A053746 A144695 A125244
Adjacent sequences: A104477 A104478 A104479 this_sequence A104481 A104482 A104483
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
William C. Brown (wcbrow00(AT)centre.edu), Apr 18 2005
|
|
|
Search completed in 0.002 seconds
|