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A104495 Matrix inverse of triangle A099602, read by rows, where row n of A099602 equals the inverse binomial transform of column n of the triangle of trinomial coefficients (A027907). +0
3
1, -1, 1, 1, -2, 1, -1, 3, -4, 1, 1, -4, 12, -5, 1, -1, 5, -34, 17, -7, 1, 1, -6, 98, -51, 32, -8, 1, -1, 7, -294, 149, -124, 40, -10, 1, 1, -8, 919, -443, 448, -164, 61, -11, 1, -1, 9, -2974, 1362, -1576, 612, -298, 72, -13, 1, 1, -10, 9891, -4336, 5510, -2188, 1294, -370, 99, -14, 1, -1, 11, -33604, 14227, -19322, 7698 (list; table; graph; listen)
OFFSET

0,5

COMMENT

Row sums are A104496. Absolute row sums form A014137 (partial sums of Catalan numbers). Column 2 is signed A014143.

FORMULA

G.f.: A(x, y) = (1 + x*y/(1+x))/(1+x - x^2*y^2*Catalan(-x)^2), also G.f.: Column_k(x) = Catalan(-x)^(2*[k/2])/(1+x)^[(k+3)/2], where Catalan(x)=(1-(1-4*x)^(1/2))/(2*x) (cf. A000108).

EXAMPLE

Rows begin:

1;

-1,1;

1,-2,1;

-1,3,-4,1;

1,-4,12,-5,1;

-1,5,-34,17,-7,1;

1,-6,98,-51,32,-8,1;

-1,7,-294,149,-124,40,-10,1;

1,-8,919,-443,448,-164,61,-11,1;

-1,9,-2974,1362,-1576,612,-298,72,-13,1; ...

PROGRAM

(PARI) {T(n, k)=local(X=x+x*O(x^n), Y=y+y*O(y^k)); polcoeff(polcoeff( (1+X*Y/(1+X))/(1+X-Y^2*(1-(1+4*X)^(1/2))^2/4), n, x), k, y)}

CROSSREFS

Cf. A099602, A027907, A000108, A104496, A014137, A014143.

Sequence in context: A137596 A111669 A124834 this_sequence A093541 A089940 A123974

Adjacent sequences: A104492 A104493 A104494 this_sequence A104496 A104497 A104498

KEYWORD

sign,tabl

AUTHOR

Paul D. Hanna (pauldhanna(AT)juno.com), Mar 11 2005

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Last modified August 19 23:53 EDT 2008. Contains 142930 sequences.


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