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Search: id:A104856
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| A104856 |
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Triangle read by rows: T(n,k)=binomial(n,k)binomial(k,floor(k/2))binomial(n-k,floor((n-k)/2)) (0<=k<=n). |
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+0
1
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| 1, 1, 1, 2, 2, 2, 3, 6, 6, 3, 6, 12, 24, 12, 6, 10, 30, 60, 60, 30, 10, 20, 60, 180, 180, 180, 60, 20, 35, 140, 420, 630, 630, 420, 140, 35, 70, 280, 1120, 1680, 2520, 1680, 1120, 280, 70, 126, 630, 2520, 5040, 7560, 7560, 5040, 2520, 630, 126, 252, 1260, 6300
(list; table; graph; listen)
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OFFSET
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0,4
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REFERENCES
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David M. Bloom, Problem 10921, Amer. Math. Monthly 110, (2003), 958-959.
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FORMULA
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T(n, k)=binomial(n, k)binomial(k, floor(k/2))binomial(n-k, floor((n-k)/2)) (0<=k<=n).
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MAPLE
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T:=(n, k)->binomial(n, k)*binomial(k, floor(k/2))*binomial(n-k, floor((n-k)/2)): for n from 0 to 10 do seq(T(n, k), k=0..n) od; # yields sequence in triangular form
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CROSSREFS
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Row sums yield A005566. T(n,0)=T(n,n)=A001405(n).
Cf. A005566, A001405.
Sequence in context: A022867 A070610 A104346 this_sequence A038715 A057040 A096235
Adjacent sequences: A104853 A104854 A104855 this_sequence A104857 A104858 A104859
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KEYWORD
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nonn,tabl
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AUTHOR
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Emeric Deutsch (deutsch(AT)duke.poly.edu), Apr 23 2005
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