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Search: id:A105063
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| A105063 |
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Define a(1)=0, a(2)=0, a(3)=8, a(4)=24 and then a(n)=66*a(n-2)+32-a(n-4) sequence such that 17*(a(n)^2)+17*a(n)+1 = a square. |
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+0
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| 0, 0, 8, 24, 560, 1616, 36984, 106664, 2440416, 7038240, 161030504, 464417208, 10625572880, 30644497520, 701126779608, 2022072419144, 46263741881280, 133426135166016, 3052705837384904, 8804102848537944, 201432321525522416
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OFFSET
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1,3
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FORMULA
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a(n) = a(n-1)+66*a(n-2) -66*a(n-3) -a(n-4) +a(n-5). G.f.: 8*x^3*(1+x)^2/((1-x)*(x^2-8*x-1)*(x^2+8*x-1)). [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Nov 13 2009]
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CROSSREFS
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Cf. A103200.
Sequence in context: A050893 A037025 A103624 this_sequence A166483 A132586 A103953
Adjacent sequences: A105060 A105061 A105062 this_sequence A105064 A105065 A105066
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KEYWORD
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nonn,new
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AUTHOR
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Pierre CAMI (pierrecami(AT)tele2.fr), Apr 05 2005
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EXTENSIONS
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More terms from R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Nov 13 2009
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