|
Search: id:A105073
|
|
|
| A105073 |
|
Define a(1)=0, a(2)=2 then a(n)=3*a(n-1)-a(n-2), a(n+1)=3*a(n)-a(n-1) and a(n+2)=3*a(n+1)-a(n)+2 This sequence is such that 20*(a(n)^2)+20*a(n)+1 = j^2 = a square. |
|
+0
1
|
|
| 0, 2, 6, 16, 44, 116, 304, 798, 2090, 5472, 14328, 37512, 98208, 257114, 673134, 1762288, 4613732
(list; graph; listen)
|
|
|
|
|
Search completed in 0.002 seconds
|
