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Search: id:A105258
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| A105258 |
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Second bi-Rauzy substitution that has the same characteristic digraph polynomial as the bi-Kenyon version: x^6-2x^4-2*x^3-x^2+2*x+1=0. |
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+0 1
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| 1, 1, 2, 1, 2, 2, 1, 3, 1, 2, 2, 1, 3, 2, 1, 3, 1, 3, 2, 1, 1, 2, 2, 1, 3, 2, 1, 3, 1, 3, 2, 1, 2, 1, 3, 1, 3, 2, 1, 1, 3, 2, 1, 2, 1, 1, 3, 2, 1, 2, 2, 1, 3, 2, 1, 3, 1, 3, 2, 1, 2, 1, 3, 1, 3, 2, 1, 1, 3, 2, 1, 2, 1, 1, 3, 2, 2, 1, 3, 1, 3, 2, 1, 1, 3, 2, 1, 2, 1, 1, 3, 2, 1, 3, 2, 1, 2, 1, 1, 3, 2, 2, 1, 1, 3
(list; graph; listen)
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OFFSET
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0,3
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COMMENT
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Matrix is: M1 = {{0, 1, 0, 0, 0, 0}, {1, 0, 1, 0, 0, 0}, {1, 0,0, 0, 0, 0}, {1, 0, 0, 0, 1, 0}, {0, 0, 0, 1, 0, 1}, {0, 0, 0, 1, 0, 0}} Polynomial is: Det[M1 - x*IdentityMatrix[6]] NSolve[Det[M1 - x*IdentityMatrix[6]] == 0, x]
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FORMULA
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1->{2}, 2->{1, 3}, 3->{1}, 4->{1, 5}, 5->{4, 6}, 6->{4}
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EXAMPLE
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Triangle form is:
{1}
{1, 2}
{1, 2, 2, 1, 3}
{1, 2, 2, 1, 3, 2, 1, 3, 1, 3, 2, 1}
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MATHEMATICA
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s[1] = {2}; s[2] = {1, 3}; s[3] = {1}; s[4] = {1, 5}; s[5] = {4, 6}; s[6] = {4}; t[a_] := Join[a, Flatten[s /@ a]]; p[0] = {1}; p[1] = t[{1}]; p[n_] := t[p[n - 1]] aa = Flatten[Table[p[n], {n, 0, 6}]]
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CROSSREFS
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Cf. A073058, A105111.
Adjacent sequences: A105255 A105256 A105257 this_sequence A105259 A105260 A105261
Sequence in context: A107030 A050362 A095686 this_sequence A109967 A000119 A097368
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KEYWORD
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nonn,uned
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AUTHOR
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Roger Bagula (rlbagulatftn(AT)yahoo.com), Apr 14 2005
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