|
Search: id:A106398
|
|
|
| A106398 |
|
Binomial transform of denominators in a Zeta function. |
|
+0 1
|
|
| 1, -1, -6, -19, -39, -66, -98, -129, -172, -330, -908, -2502, -5955, -12107
(list; graph; listen)
|
|
|
OFFSET
|
1,3
|
|
|
COMMENT
|
The formula 1/Zeta(s) = 1 - 1/2^s - 1/3^s - 1/5^s + 1/6^s is shown on p. 249 of Derbyshire and relies upon strategies pioneered by Euler.
|
|
REFERENCES
|
John Derbyshire, "Prime Obsession, Bernhard Riemann and the Greatest Unsolved Problem in Mathematics", Joseph Henry Press, 2003, p. 249.
|
|
FORMULA
|
Given 1/Zeta(s) = 1 -1/2^s - 1/3^s - 1/5^s + 1/6^s - 1/7^s + 1/10^s - 1/11^s...; we apply the binomial transform to the terms: [1, -2, -3, -5, 6, -7, 10, -11, -13, 14, 15, -17, -19, 21...) which is the set of square-free deficient numbers (A087246), along with the Mobius function of each term.
|
|
EXAMPLE
|
The terms 1, 2, 3, 5, 6, 7... = A087246, square-free numbers. Applying the Mobius function rules to each of these, we get 1, -2, -3, -5, 6.... the Modius function rules are:
Given the domain N, the natural numbers 1,2,3...,
Mu(1) = 1; Mu(n) of N = 0 if n has a square factor; Mu(n) = -1 if n is a prime or the product of an odd number of different primes; Mu(n) = 1 if n is the product of an even numbers of different primes.
|
|
CROSSREFS
|
Cf. A087246, A008683.
Sequence in context: A031014 A010899 A090381 this_sequence A054567 A096957 A035495
Adjacent sequences: A106395 A106396 A106397 this_sequence A106399 A106400 A106401
|
|
KEYWORD
|
sign
|
|
AUTHOR
|
Gary W. Adamson (qntmpkt(AT)yahoo.com), May 01 2005
|
|
|
Search completed in 0.002 seconds
|