0,4

Consider the following rooted trees useful in the combinatorial game theory: each tree has zero or more subtrees at its left side and zero or more subtrees at its right side. The orientation of the subtrees among the other branches of the same side is not distinguished and all the subtrees of the same side are distinct from each other. These kind of trees map bijectively to nonnegative integers by the following map f: f(empty tree) = 0 and f(tree with left subtrees Tl1, ..., Tlj and right subtrees Tr1, ..., Trk) = 2^(2*f(Tl1)) + ... + 2^(2*f(Tlj)) + 2^((2*f(Tr1))+1) + ... + 2^((2*f(Trk))+1). The ten game trees given on page 40 of "Winning Ways" thus translate to values Game 0 -> 0, Game 1 -> 1, Game -1 -> 2, Game 2 -> 4, Game 1/2 -> 9, Game 1/4 -> 524289, Game * -> 3, Game 1* -> 12, Game *2 -> 195, Game ^ (up) -> 129. However, this correspondence is not bijective with the computed equivalence classes of games, as many integers map to game trees with dominated o r reversible options. Here a(n) gives the total number of edges in the tree f(n).

E. R. Berlekamp, J. H. Conway and R. K. Guy, Winning Ways, Second Edition, Vol. 1, A K Peters, 2001, p. 40.

3 = 2^0 + 2^1 = 2^(2*0) + 2^((2*0)+1) encodes the CGT tree \/ which has two edges, thus a(3)=2.

64 = 2^6 = 2^(2*3), i.e. it encodes the CGT tree

\/

.\

which has three edges, so a(64)=3.

(MIT Scheme:) (define (A106486 n) (cond ((zero? n) 0) (else (fold-left (lambda (x y) (+ x y 1)) 0 (map A106486 (map shr (on-bit-indices n))))))) (define (shr n) (if (odd? n) (/ (- n 1) 2) (/ n 2))) (define (on-bit-indices n) (let loop ((n n) (i 0) (c (list))) (cond ((zero? n) (reverse! c)) ((odd? n) (loop (/ (- n 1) 2) (1+ i) (cons i c))) (else (loop (/ n 2) (1+ i) c)))))

Number of leaves: A106487, negating automorphism: A106485.

Sequence in context: A071508 A085561 A116370 this_sequence A106494 A015135 A116619

Adjacent sequences: A106483 A106484 A106485 this_sequence A106487 A106488 A106489

nonn

Antti Karttunen (His-Firstname.His-Surname(AT)iki.fi), May 21 2005