|
Search: id:A107097
|
|
|
| A107097 |
|
G.f. satisfies: A(A(x)) = A(x)/(1-x), so that the self-COMPOSE transform generates partial sums (A107098). |
|
+0
2
|
|
| 0, 1, 1, 0, 1, -3, 13, -63, 339, -1982, 12429, -82827, 582589, -4303016, 33240205, -267697961, 2241725581, -19477340744, 175259713769, -1630583565434, 15663877511863, -155168272246709, 1583282220672515, -16623104947488348, 179409709469784087, -1988706708427161585
(list; graph; listen)
|
|
|
OFFSET
|
0,6
|
|
|
FORMULA
|
G.f. equals series reversion of g.f. for signed A030266.
|
|
EXAMPLE
|
Series reversion of g.f.:
x + x^2 + x^4 - 3*x^5 + 13*x^6 - 63*x^7 + 339*x^8 -+...
equals g.f. of signed A030266:
x - x^2 + 2*x^3 - 6*x^4 + 23*x^5 - 104*x^6 + 531*x^7 -+...
|
|
PROGRAM
|
(PARI) {a(n)=local(A, B, F); if(n<1, 0, F=x+2*x^2-3*x^3+x*O(x^n); A=F; for(j=0, n, for(i=0, j, B=serreverse(A); A=(A+subst(B, x, A/(1-x)))/2); A=round(A)); polcoeff(A, n, x))}
|
|
CROSSREFS
|
Cf. A107098.
Sequence in context: A130525 A000259 A007855 this_sequence A006923 A011272 A065065
Adjacent sequences: A107094 A107095 A107096 this_sequence A107098 A107099 A107100
|
|
KEYWORD
|
sign
|
|
AUTHOR
|
Paul D. Hanna (pauldhanna(AT)juno.com), May 12 2005
|
|
|
Search completed in 0.004 seconds
|
