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A107793 Gaps in ones order in the tribonacci substitution of three symbols. +0
1
4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 3, 5, 4, 5, 5 (list; graph; listen)
OFFSET

0,1

COMMENT

Average gap=N[Apply[Plus, b]/Length[b]]=4.38095

FORMULA

1->(2), 2->{3}, 3->{1, 2, 3}, a(n) = orderones[n]-ordersones[n-1] gap in order of appearance of ones in the substitution

MATHEMATICA

s[1] = {2}; s[2] = {3}; ; s[3] = {1, 2, 3}; t[a_] := Flatten[s /@ a]; p[0] = {1}; p[1] = t[p[0]]; p[n_] := t[p[n - 1]] pp = p[13] a = Flatten[Table[If[pp[[j]] == 1, j, {}], {j, 1, Length[pp]}]] b = Table[a[[n]] - a[[n - 1]], {n, 2, Length[a]}]

CROSSREFS

Cf. A000045, A000213, A000931.

Sequence in context: A138753 A069197 A021692 this_sequence A004493 A019836 A020503

Adjacent sequences: A107790 A107791 A107792 this_sequence A107794 A107795 A107796

KEYWORD

nonn,uned

AUTHOR

Roger L. Bagula (rlbagulatftn(AT)yahoo.com), Jun 11 2005

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Last modified December 5 20:25 EST 2009. Contains 170428 sequences.


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