|
Search: id:A108287
|
|
|
| A108287 |
|
Consider the Diophantine equations x+y=a, x^2+y^2=b, x^3+y^3=c. There are three values of a for each pair b,c with b>0 and c>0. Sequence gives values of b. |
|
+0 2
|
|
| 1, 4, 7, 9, 13, 16, 19, 21, 25, 28, 31, 36, 37, 39, 43, 49, 49, 52, 57, 61, 63, 64, 67, 73, 76, 79, 81, 84, 91, 91, 93, 97, 100, 103, 109, 111, 112, 117, 121, 124, 127
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
PROGRAM
|
InputMode:=Word
[x+y=a, x^2+y^2=b, x^3+y^3=c]
"Find integer values of a, b and c."
; Simp(User)
(x+y)^2=a^2
; Expd(#4)
x^2+2*x*y+y^2=a^2
; Simp(User)
2*x*y=a^2-b
; Simp(User)
x*y=(a^2-b)/2
; Simp(User)
x^2-x*y+y^2=c/(x+y)
; Simp(Sub(User'))
-x*y=c/a-b
; Simp(User)
0=(a^3-3*a*b+2*c)/(2*a)
a^3-3*a*b+2*c=0
"Let d be a integer solution for a."
; Simp(User)
(a^3-3*a*b+2*c)/(a-d)=0
; Expd(#13)
(3*b*d-2*c-d^3)/(a-d)-a^2-a*d+3*b-d^2=0
"The other two solutions are solutions of these equations."
(3*b*d-2*c-d^3)/(a-d)=0
-a^2-a*d+3*b-d^2=0
; Simp(User)
c=d*(3*b-d^2)/2
; Simp(Solve(#17, a))
a=(SQRT(3)*SQRT(4*b-d^2)-d)/2 OR a=-(SQRT(3)*SQRT(4*b-d^2)+d)/2
LIST_TO_SET(v):=MAP_LIST(v SUB i, i, {1, ..., DIM(v)})
VECTOR(VECTOR(SUBST(a^3-3*a*b+2*c, [b, c], [x SUB 1, x SUB 2]), a, x SUB 3), x, a11)
"Let e be the second integer solution for a."
e=(SQRT(3)*SQRT(4*b-d^2)-d)/2
b=(d^2+d*e+e^2)/3
c=d*(3*b-d^2)/2
; Simp(User)
c=d*e*(d+e)/2
f=-(SQRT(3)*SQRT(4*b-d^2)+d)/2
; Simp(User)
f=-d-e
a9:=VECTOR(VECTOR([(d^2+d*e+e^2)/3, d*e*(d+e)/2, [d, e, -d-e]], e, d, 32), d, 1, 32)
a10:=SELECT(INTEGER?(x SUB 1) AND INTEGER?(x SUB 2), x, APPEND(a9))
a11:=SORT(a10)
; Simp(#31)
|
|
CROSSREFS
|
For values of c see A108940.
Sequence in context: A047537 A062458 A080902 this_sequence A082869 A166569 A024608
Adjacent sequences: A108284 A108285 A108286 this_sequence A108288 A108289 A108290
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
James R FitzSimons (cherry(AT)getnet.net), Jun 22 2007
|
|
|
Search completed in 0.002 seconds
|