|
Search: id:A108575
|
|
|
| A108575 |
|
Numbers n such that continued fraction for sqrt(n) is multiplicative. |
|
+0
1
|
|
| 3, 7, 8, 13, 14, 15, 22, 23, 24, 32, 33, 34, 35, 44, 47, 48, 58, 59, 60, 62, 63, 74, 75, 78, 79, 80, 95, 96, 98, 99, 114, 119, 120, 135, 136, 138, 140, 141, 142, 143, 160, 162, 164, 167, 168, 185, 187, 189, 192, 194, 195, 215, 219, 220, 222, 223, 224, 248, 252, 254
(list; graph; listen)
|
|
|
OFFSET
|
1,1
|
|
|
COMMENT
|
k^2-k < a(n) < k^2 for some k.
|
|
EXAMPLE
|
Continued fraction for sqrt(7) is a = (2,1,1,1,4,1,1,1,4,...). If we index starting at 0, so that a(0) = 2, a is multiplicative (the value at a(0) is immaterial). Hence 7 is in the sequence.
|
|
CROSSREFS
|
Sequence in context: A153030 A031425 A063657 this_sequence A153219 A050014 A132017
Adjacent sequences: A108572 A108573 A108574 this_sequence A108576 A108577 A108578
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
David W. Wilson (davidwwilson(AT)comcast.net), Jun 10 2005
|
|
|
Search completed in 0.002 seconds
|
