|
Search: id:A108710
|
|
|
| A108710 |
|
Start to read the sequence digit by digit and erase the first "1" you encounter, then the "first "2", the first "3", etc., until the first "0"; go on from there and erase again the first "1", the first "2", etc., until "0" -- and so on, cyclically until the end of the (infinite) sequence. Concatenate what is left. The result is the concatenation of all integers of the sequence. |
|
+0
1
|
|
| 1, 12, 13, 24, 153, 627, 4819, 5031, 6223, 7445, 8617, 985900, 3112632, 4253677, 4849508, 16213749, 58657980, 90031121, 324653627, 482950316, 2737445864, 7985900811, 26324153677, 489950816253, 74958607980900, 311213241536274
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
Fractal-like sequence
|
|
EXAMPLE
|
Sequence starts: 1 12 13 24 153 627 4819 5031... Erasing cyclically digits 1 --> 0 gives: . 1. 1. 2. 1.3 .2. 4.1. 5.3. which is the pattern of the sequence itself.
|
|
CROSSREFS
|
Sequence in context: A123132 A050840 A118068 this_sequence A108709 A138821 A022102
Adjacent sequences: A108707 A108708 A108709 this_sequence A108711 A108712 A108713
|
|
KEYWORD
|
base,easy,nonn
|
|
AUTHOR
|
Eric Angelini (eric.angelini(AT)kntv.be), Jun 20 2005
|
|
|
Search completed in 0.002 seconds
|
