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Search: id:A108993
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| A108993 |
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a(n) = A108992(n)/(n+1). A(x) = 1/x*series_reversion(x/G108996(x)) where G108996(x) is g.f. of A108996. |
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7
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| 1, 1, 3, 19, 205, 3276, 70852, 1953715, 65904057, 2639266228, 122677374326, 6503266277223, 387708627582311, 25700183133977665, 1876381387159576676, 149695388098709302361, 12961535832843534300945
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OFFSET
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0,3
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COMMENT
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A108992 is the second diagonal of triangle A108990, in which the g.f. of row n, R_n(x), satisfies: [x^k] R_{n+1}(x) = [x^k] (1 + x*R_n(x))^(n+1) for k=0..n+1.
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PROGRAM
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(PARI) {a(n)=local(F=1+x*O(x^n)); for(m=1, n+1, F=(1+x*F)^m); polcoeff(F, n)/(n+1)}
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CROSSREFS
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Cf. A108990, A108991, A108992, A108994, A108995, A108996.
Sequence in context: A007151 A127502 A027546 this_sequence A052886 A079144 A049056
Adjacent sequences: A108990 A108991 A108992 this_sequence A108994 A108995 A108996
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KEYWORD
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nonn
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AUTHOR
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Paul D. Hanna (pauldhanna(AT)juno.com), Jun 15 2005
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