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Search: id:A110215
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| A110215 |
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Inequivalent coverings of a cubic board with the minimal number of knights. |
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+0 3
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OFFSET
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1,4
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FORMULA
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Sequence A110214 gives minimal number of knights needed to cover an n X n X n board. This sequence gives the number of inequivalent solutions to cover an n X n X n board using A110214(n) knights.
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EXAMPLE
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a(3) = 1, since up to rotations and reflections,
OOO KKK OOO
OKO OKO OKO
OOO OOO OOO is the only covering for n = 3.
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CROSSREFS
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This sequence is a 3-dimensional analogue of A006076. a(n) = A110218(n, n, n). A110216 gives total number of solutions.
Sequence in context: A126756 A058823 A050536 this_sequence A052387 A001780 A053296
Adjacent sequences: A110212 A110213 A110214 this_sequence A110216 A110217 A110218
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KEYWORD
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hard,nonn
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AUTHOR
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Nikolaus Meyberg (Nikolaus.Meyberg(AT)t-online.de), Jul 17 2005
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