|
Search: id:A110303
|
|
| |
|
| 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75
(list; graph; listen)
|
|
|
OFFSET
|
0,2
|
|
|
COMMENT
|
An alternating integer is a positive integer for which, in base-10, the parity of its digits alternates. E.g. 121 is alternating because its consecutive digits are odd-even-odd, 1 being odd and 2 even. Of course, 1234567890 is also alternating. An alternator is a positive integer which has a multiple which is alternating.
|
|
REFERENCES
|
45th International Mathematical Olympiad (45th IMO), Problem #6 and Solution, Mathematics Magazine, 2005, Vol. 78, No. 3, pp. 247, 250-251.
|
|
LINKS
|
Walter Nissen, Home Page (listed in lieu of email address)
|
|
FORMULA
|
positive n, not congruent to 0 mod 20
|
|
EXAMPLE
|
11 is an alternator and in the sequence because it has a multiple which is
alternating. The least of these multiples is 121.
|
|
CROSSREFS
|
Cf. A030141, A110304, A110305.
Sequence in context: A096105 A051108 A051107 this_sequence A084981 A078453 A052425
Adjacent sequences: A110300 A110301 A110302 this_sequence A110304 A110305 A110306
|
|
KEYWORD
|
base,easy,nonn
|
|
AUTHOR
|
Walter Nissen Jul 18 2005
|
|
|
Search completed in 0.002 seconds
|