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Search: id:A110354
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| A110354 |
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Rearrangement of natural numbers such that digit 'd' occurs exactly 'd' times. Once a cycle is completed i.e. 9 occurs 9 times. The same is repeated. The first number of the second cycle would be a number containing 1 once and which has not occurred earlier. |
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+0
1
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| 1, 2, 23, 3, 34, 4, 44, 5, 55, 56, 65, 6, 66, 67, 7, 77, 777, 8, 88, 89, 98, 888, 9, 99, 9999, 13
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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Needs better description. Is the sequence finite?
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EXAMPLE
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One cycle is complete at a(25). From a(1) to a(25), 1 occurs once, 2 occurs twice,..., 9 occurs 9 times etc.{ Note: a(25) = 9999 and not 999.} The second cylce starts at a(26) and a(26) = 13 as 12 has already occurred.
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CROSSREFS
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Sequence in context: A107801 A076653 A114008 this_sequence A162711 A120713 A104644
Adjacent sequences: A110351 A110352 A110353 this_sequence A110355 A110356 A110357
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KEYWORD
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base,nonn,obsc,uned
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AUTHOR
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Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Jul 22 2005
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