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Search: id:A111569
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| A111569 |
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a(n) = a(n-1) + a(n-3) + a(n-4), a(0) = -1, a(1) = 1, a(2) = 2, a(3) = 1. |
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6
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| -1, 1, 2, 1, 1, 4, 7, 9, 14, 25, 41, 64, 103, 169, 274, 441, 713, 1156, 1871, 3025, 4894, 7921, 12817, 20736, 33551, 54289, 87842, 142129, 229969, 372100, 602071, 974169, 1576238, 2550409, 4126649, 6677056, 10803703, 17480761, 28284466, 45765225
(list; graph; listen)
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OFFSET
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0,3
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COMMENT
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In reference to the program code given, 4*tesseq[A*H] = A001638 (a Fielder sequence) where A001638(2n)=L(n)^2. Here we have: a(2n+1) = A007598(n+1) = Fib(n+1)^2,
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REFERENCES
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Fielder, Daniel C.; Special integer sequences controlled by three parameters. Fibonacci Quart 6 1968 64-70.
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FORMULA
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G.f. (1-2*x-x^2)/((x^2+x-1)*(1+x^2)).
a(n) = 2*A056594(n+3)/5-6*A056594(n)/5+A000032(n+1)/5. [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Nov 12 2009]
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PROGRAM
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Floretion Algebra Multiplication Program, FAMP Code: 4kbaseiseq[B+H] with B = - .25'i + .25'j - .25i' + .25j' + k' - .5'kk' - .25'ik' - .25'jk' - .25'ki' - .25'kj' - .5e and H = + .75'ii' + .75'jj' + .75'kk' + .75e
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CROSSREFS
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Cf. A001638, A111570, A111571, A111572, A111573, A007598, A000045.
Sequence in context: A141036 A011016 A096540 this_sequence A055130 A051292 A094424
Adjacent sequences: A111566 A111567 A111568 this_sequence A111570 A111571 A111572
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KEYWORD
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easy,sign,new
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AUTHOR
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Creighton Dement (creighton.k.dement(AT)uni-oldenburg.de), Aug 07 2005
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