Logo

Greetings from The On-Line Encyclopedia of Integer Sequences!

Hints

Search: id:A111845
Displaying 1-1 of 1 results found. page 1
     Format: long | short | internal | text      Sort: relevance | references | number      Highlight: on | off
A111845 Triangle P, read by rows, that satisfies [P^4](n,k) = P(n+1,k+1) for n>=k>=0, also [P^(4*m)](n,k) = [P^m](n+1,k+1) for all m, where [P^m](n,k) denotes the element at row n, column k, of the matrix power m of P, with P(k,k)=1 and P(k+1,1)=P(k+1,0) for k>=0. +0
6
1, 1, 1, 4, 4, 1, 40, 40, 16, 1, 1040, 1040, 544, 64, 1, 78240, 78240, 48960, 8320, 256, 1, 18504256, 18504256, 13110400, 2878720, 131584, 1024, 1, 14463224448, 14463224448, 11192599808, 2982187520, 180270080, 2099200, 4096, 1 (list; table; graph; listen)
OFFSET

0,4

COMMENT

Column 0 and column 1 are equal for n>0.

FORMULA

Let q=4; the g.f. of column k of P^m (ignoring leading zeros) equals: 1 + Sum_{n>=1} (m*q^k)^n/n! * Product_{j=0..n-1} L(q^j*x) where L(x) satisfies: x = Sum_{n>=1} -(-1)^n/n!*Product_{j=0..n-1} L(q^j*x); L(x) equals the g.f. of column 0 of the matrix log of P (A111849).

EXAMPLE

Let q=4; the g.f. of column k of matrix power P^m is:

1 + (m*q^k)*L(x) + (m*q^k)^2/2!*L(x)*L(q*x) +

(m*q^k)^3/3!*L(x)*L(q*x)*L(q^2*x) +

(m*q^k)^4/4!*L(x)*L(q*x)*L(q^2*x)*L(q^3*x) + ...

where L(x) satisfies:

x = L(x) - L(x)*L(q*x)/2! + L(x)*L(q*x)*L(q^2*x)/3! -+ ...

and L(x) = x + 4/2!*x^2 + 56/3!*x^3 + 1728/4!*x^4 +...(A111849).

Thus the g.f. of column 0 of matrix power P^m is:

1 + m*L(x) + m^2/2!*L(x)*L(4*x) + m^3/3!*L(x)*L(4*x)*L(4^2*x) +

m^4/4!*L(x)*L(4*x)*L(4^2*x)*L(4^3*x) + ...

Triangle P begins:

1;

1,1;

4,4,1;

40,40,16,1;

1040,1040,544,64,1;

78240,78240,48960,8320,256,1;

18504256,18504256,13110400,2878720,131584,1024,1; ...

where P^4 shifts columns left and up one place:

1;

4,1;

40,16,1;

1040,544,64,1;

78240,48960,8320,256,1; ...

PROGRAM

(PARI) {P(n, k, q=4)=local(A=Mat(1), B); if(n<k|k<0, 0, for(m=1, n+1, B=matrix(m, m); for(i=1, m, for(j=1, i, if(j==i, B[i, j]=1, if(j==1, B[i, j]=(A^q)[i-1, 1], B[i, j]=(A^q)[i-1, j-1])); )); A=B); return(A[n+1, k+1]))}

CROSSREFS

Cf. A111846 (column 0), A111847 (row sums), A111848 (matrix log), A111840 (q=3), A078536 (variant).

Sequence in context: A071207 A136214 A067328 this_sequence A120396 A141024 A058888

Adjacent sequences: A111842 A111843 A111844 this_sequence A111846 A111847 A111848

KEYWORD

nonn,tabl

AUTHOR

Paul D. Hanna (pauldhanna(AT)juno.com), Aug 23 2005

page 1

Search completed in 0.002 seconds

Lookup | Welcome | Find friends | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Transforms | Puzzles | Hot | Classics
More pages | Superseeker | Maintained by N. J. A. Sloane (njas@research.att.com)

Last modified December 4 08:07 EST 2009. Contains 170310 sequences.


AT&T Labs Research