|
Search: id:A111890
|
|
|
| A111890 |
|
Number of numbers m <= n such that 0 equals the second digit after decimal point of square root of n in decimal representation. |
|
+0 12
|
|
| 1, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 8, 8, 8, 8, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 13, 13, 14, 14, 14, 14, 14, 14
(list; graph; listen)
|
|
|
OFFSET
|
1,4
|
|
|
COMMENT
|
For n>1: if A111862(n)=4 then a(n)=a(n-1)+1 else a(n)=a(n-1).
a(n)/n --> 1/10.
|
|
REFERENCES
|
G. Polya and G. Szego, Problems and Theorems in Analysis I (Springer 1924, reprinted 1972), Part Two, Chap. 4, Sect. 4, Problem 178.
|
|
EXAMPLE
|
a(10) = 3, a(100) = 15, a(1000) = 104, a(10000) = 1006.
|
|
CROSSREFS
|
Cf. A111891, A111892, A111893, A111894, A111895, A111896, A111897, A111898, A111899, A111850.
Sequence in context: A025811 A034258 A090663 this_sequence A104277 A125893 A005857
Adjacent sequences: A111887 A111888 A111889 this_sequence A111891 A111892 A111893
|
|
KEYWORD
|
nonn,base
|
|
AUTHOR
|
Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Aug 20 2005
|
|
|
Search completed in 0.002 seconds
|