0,3

a(n) = a(a(n-2)) + a(n-a(n-1)) a(0) = a(1) = 1

a[n_] := a[n] = a[a[n - 2]] + a[n - a[n - 1]] a[0] = a[1] = 1; Table[a[n], {n, 0, 58}]

Adjacent sequences: A113883 A113884 A113885 this_sequence A113887 A113888 A113889

Sequence in context: A140357 A089265 A113885 this_sequence A122376 A067240 A126080

easy,fini,full,nonn

Josh Locker (joshlocker(AT)gmail.com), Jan 28 2006