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Search: id:A114118
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| A114118 |
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Number triangle T(n,k)=sum{j=0..n, C(floor((n+k+j)/3),k)C(k,floor((n+k+j)/3))}. |
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+0
2
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| 1, 2, 1, 1, 3, 1, 0, 2, 3, 1, 0, 1, 3, 3, 1, 0, 0, 2, 3, 3, 1, 0, 0, 1, 3, 3, 3, 1, 0, 0, 0, 2, 3, 3, 3, 1, 0, 0, 0, 1, 3, 3, 3, 3, 1, 0, 0, 0, 0, 2, 3, 3, 3, 3, 1, 0, 0, 0, 0, 1, 3, 3, 3, 3, 3, 1, 0, 0, 0, 0, 0, 2, 3, 3, 3, 3, 3, 1, 0, 0, 0, 0, 0, 1, 3, 3, 3, 3, 3, 3, 1, 0, 0, 0, 0, 0, 0, 2, 3, 3, 3, 3, 3, 3, 1
(list; table; graph; listen)
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OFFSET
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0,2
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COMMENT
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Row sums are A114119. Diagonal sums are A008619(n+1).
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EXAMPLE
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Triangle begins
1...........................= 1 = 1 mod 3
2,1.........................= 3 = 0 mod 3
1,3,1.......................= 5 = 2 mod 3
0,2,3,1.....................= 6 = 0 mod 3
0,1,3,3,1...................= 8 = 2 mod 3
0,0,2,3,3,1.................= 9 = 0 mod 3
0,0,1,3,3,3,1...............= 11 = 2 mod 3
0,0,0,2,3,3,3,1.............= 12 = 0 mod 3
0,0,0,1,3,3,3,3,1...........= 14 = 2 mod 3
0,0,0,0,2,3,3,3,3,1.........= 15 = 0 mod 3
0,0,0,0,1,3,3,3,3,3,1.......= 17 = 2 mod 3
0,0,0,0,0,2,3,3,3,3,3,1.....= 18 = 0 mod 3
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CROSSREFS
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Sequence in context: A103910 A155993 A147867 this_sequence A146014 A106177 A135010
Adjacent sequences: A114115 A114116 A114117 this_sequence A114119 A114120 A114121
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KEYWORD
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easy,nonn,tabl
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AUTHOR
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Paul Barry (pbarry(AT)wit.ie), Nov 13 2005
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